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20 this code puts the first 700 fibonacci numbers in a list Here at first, you have declared a to hold an integer type and later you have assigned a function to it and so its type now became a function. Using meaningful variable names helps improve readability

Fibonacci_numbers = [0, 1] for i in range(2,700) The type of a variable is determined at runtime and it can vary as the execution is in progress If you're using python < 3, use xrange instead of range.

I'm just trying to improve my programming skill by making some basic functions

I want to fill a list with fibonacci values, but i think my code gives the sum of all the numbers put together and p. A close practical example is the fibonacci sequence I reasonably searched hard through available python code for this sequence There were tons, most often too cryptic for my basic grasp

I came up with this one Simple and should do the job A = 1 b = 0 print (b) print(a) for i in range(0,100) C = b b = a a = c + b print(a)

I'm thinking i could use separate functions but i can't figure out how to pass the argument that calculates the fibonacci sequence

Then the next step would be to to print out the sequence of numbers up to that number. Hello i am trying to write a script that prompts the user for an integer number (n), then prints all the fibonacci numbers that are less than or equal to the input, in that order Anyone know the most efficient way of displaying the first 100 numbers in the fibonacci sequence in python please Here is my current code

I wrote that code, b. Alternative implementation following kebertx’s example, here is a solution i would personally make in python Of course, if you were to process many fibonacci values, you might even want to combine those two solutions and create a cache for the numbers A, b = 0, 1 for i in range(0, n)

A, b = b, a + b return a

Python is a dynamically typed language

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